Magnetic field in a plane electromagnetic wave is given by, B→=B_0sinkx+ωtj^ T. Expression for corresponding electric field will be: (Where c is speed of light)

Correct answer: (C) E→=B_0csinkx+ωtk^ V m^(-1). For electromagnetic wave speed of light is given by c=E_0B_0 Electric field is expressed as E_0=cB_0 , E→ is ⊥ to direction x and direction of B→ The expression of electric field is E→=cB_0 sin⁡(kx+wt)k^ V m^(-1)

Q88 / 90 · JEE Main 2017 (08 Apr Online) · Physics

Magnetic field in a plane electromagnetic wave is given by,

$\vec{B} = B_{0} \sin (k x + ω t) \hat{j} T$ . Expression for corresponding electric field will be:

(Where $c$ is speed of light)

A
$\vec{E} = - B_{0} c \sin (k x + ω t) \hat{k} V m^{- 1}$
B
$\vec{E} = B_{0} c \sin (k x - ω t) \hat{k} V m^{- 1}$
Correct answer
C
$\vec{E} = B_{0} c \sin (k x + ω t) \hat{k} V m^{- 1}$
D
$\vec{E} = \frac{B_{0}}{c} \sin (k x + ω t) \hat{k} V m^{- 1}$

Solution

For electromagnetic wave speed of light is given by

$c = \frac{E_{0}}{B_{0}}$
Electric field is expressed as $E_{0} = c B_{0}, \vec{E} i s ⊥ to direction x and direction o f \vec{B}$

The expression of electric field is $\vec{E} = c B_{0} s i n (k x + w t) \hat{k} V m^{- 1}$

Hence, the correct answer is option: 'C'.

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Magnetic field in a plane electromagnetic wave is given by,B→=B0sinkx+ωtj^ T. Expression for corresponding electric field will be:(Where c is speed of light)

Solution

Relevant Questions

Magnetic field in a plane electromagnetic wave is given by,

$\vec{B} = B_{0} \sin (k x + ω t) \hat{j} T$ . Expression for corresponding electric field will be:

(Where $c$ is speed of light)