Q38 / 97 · NTA Abhyas (JEE Main) 2020 · Physics · Nuclear Physics

Mpdenotes the mass of a proton and Mn that of a neutron. A given nucleus, of binding energy B, contains Z protons and N neutrons. The mass M(N, Z) of the nucleus is given by (c is the velocity of light)

  • A
    M(N, Z)=NMn+ZMp-Bc2
  • B
    MN, Z=NMn+ZMp+Bc2
  • Correct answer
    C
    M(N, Z)=NMn+ZMp-B/c2
  • D
    MN, Z=NMn+ZMp+B/c2

Solution

Mass defect = mass of nucleon - mass of nucleus

B= ZMp+NMn-MN,Zc2

⇒M(M, Z)=ZMp+NMn-B/c2

Hence, the correct answer is option: 'C'.

More Nuclear Physics Questions