Line (x+1)/(λ)=y-1=(z+2)/(-4) is perpendicular to 2x+2y-8z+5=0, then λ is

Correct answer: (A) 1. When line (x-x_1a_1=y-y_1b_1=z-z_1c_1 is perpendicular to plane ax+by+cz+d=0, thena_1a=b_1b=c_1c∴ λ2=12=-4)/(-8) ⇒λ=1 Hence, option (a) is correct.

Q60 / 125 · BITSAT 2018 · Mathematics

Line $\frac{(x + 1)}{λ} = y - 1 = \frac{(z + 2)}{- 4}$ is perpendicular to $2 x + 2 y - 8 z + 5 = 0$ , then $λ$ is

Correct answer
A
$1$
B
$- 4$
C
$- 5$
D
$- 3$

Solution

When line $\frac{x - x_{1}}{a_{1}} = \frac{y - y_{1}}{b_{1}} = \frac{z - z_{1}}{c_{1}}$ is perpendicular to plane $a x + b y + c z + d = 0$ , then

$\frac{a_{1}}{a} = \frac{b_{1}}{b} = \frac{c_{1}}{c}$

$∴ \frac{λ}{2} = \frac{1}{2} = \frac{- 4}{- 8}$

$\Rightarrow λ = 1$

Hence, option (a) is correct.

Hence, the correct answer is option: 'A'.

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Line x+1λ=y-1=z+2-4 is perpendicular to 2x+2y-8z+5=0, then λ is

Solution

Relevant Questions

Line $\frac{(x + 1)}{λ} = y - 1 = \frac{(z + 2)}{- 4}$ is perpendicular to $2 x + 2 y - 8 z + 5 = 0$ , then $λ$ is