Q88 / 180 · AIIMS 2018 (26 May) · Physics

Light is incident on a polarizer with intensity $I_0$. A second prism called analyzer is kept at a angle of $15^{\circ}$, from the first polarizer then the intensity of final emergent light will be

  • A
    $I_0(\sqrt{2}-1)$
  • B
    $I_0(\sqrt{3}-1)$
  • Correct answer
    C
    $\frac{I_0}{4}(2+\sqrt{3})$
  • D
    $\frac{I_0}{4}(2-\sqrt{3})$

Solution

Intensity of final emergent light $\begin{aligned} & I=\frac{I_0}{2} \cos ^2\left(15^{\circ}\right)==\frac{I_0}{4}\left[1+\cos \left(30^{\circ}\right)\right] \\ & =\frac{I_0}{4} \cdot\left[1+\frac{\sqrt{3}}{2}\right]=\frac{I_0}{4}[2+\sqrt{3}]\end{aligned}$

Hence, the correct answer is option: 'C'.

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