Q22 / 160 · TS EAMCET 2020 (09 Sep Shift 1) · Chemistry

LiCoO2 crystallizes in a rhombohedral structure. Consider a situation where 50% lithium Li is extracted from the lattice. To keep the crystal electrically neutral. change in average oxidation state of Co is

  • A
    16.66% decrease
  • Correct answer
    B
    16.66% increase
  • C
    50% increase
  • D
    50% decrease

Solution

LiCoO2 The oxidation state of lithium is +1 and oxygen will show -2.Let oxidation state of Co is xSo, LiCoO2; 1×1+x+2(-2)=0                      x+1-4=0                          x=3After 50% lithium extraction the formula become:-Li0.5CoO2Then, Li0.5CoO2; 1×0.5+x+2(-2)=0                      x+0.5-4=0                          x=3.5So change in oxidation state of Co =3.5-3.0=0.5Percentage in increase=0.53=16.66%So, change in oxidation state is 16.66 increase.

Hence, the correct answer is option: 'B'.

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