Let $\left[x\right]$ be the greatest integer less than or equal to $x$, for a real number $x$. Then the following sum

$\left[\frac{2^{2020}+1}{2^{2018}+1}\right]+\left[\frac{3^{2020}+1}{3^{2018}+1}\right]+\left[\frac{4^{2020}+1}{4^{2018}+1}\right]+\left[\frac{5^{2020}+1}{5^{2018}+1}\right]+\left[\frac{6^{2020}+1}{6^{2018}+1}\right]$

is :-

• A

  $80$
• Correct answer
  B

  $85$
• C

  $90$
• D

  $95$

Hence, the correct answer is option: 'B'.