Let x=(a^2b^2)/c be the physical quantity. If the percentage error in the measurement of physical quantities a, b and c is 2, 3 and 4 percent…

Question

Let x=(a^2b^2)/c be the physical quantity. If the percentage error in the measurement of physical quantities a, b and c is 2, 3 and 4 percent respectively then percentage error in the measurement of x is

MARKS Content Team · Accepted Answer

Correct answer: (B) 14%. (Δx)/x =2(Δa)/a +2(Δb)/b +(Δc)/c (Δx)/y =2×2+2×3+4 =4+6+4 (Δx)/x =14%

Let $x = [\frac{a^{2} b^{2}}{c}]$ be the physical quantity. If the percentage error in the measurement of physical quantities $a$ , $b$ and $c$ is $2$ , $3$ and $4$ percent respectively then percentage error in the measurement of $x$ is

Solution

More Units and Dimensions Questions

Let x=a2b2c be the physical quantity. If the percentage error in the measurement of physical quantities a, b and c is 2, 3 and 4 percent respectively then percentage error in the measurement of x is

Solution

More Units and Dimensions Questions

Let $x = [\frac{a^{2} b^{2}}{c}]$ be the physical quantity. If the percentage error in the measurement of physical quantities $a$ , $b$ and $c$ is $2$ , $3$ and $4$ percent respectively then percentage error in the measurement of $x$ is