Q50 / 90 · JEE Main 2021 (26 Feb Shift 2) · Mathematics

Let X1,X2,…,X18 be eighteen observations such that ∑i=118Xi-α=36 and ∑i=118Xi-β2=90, where α and β are distinct real numbers. If the standard deviation of these observations is 1, then the value of α-β is _______.

Correct answer: 4

Solution

∑i=118xi-α=36,∑i=118xi-β2=90

⇒∑i=118xi=18α+2,∑i=118xi2-2β∑i=118xi+18β2=90

Hence ∑xi2=90-18β2+36βα+2

Given ∑xi218-∑xi182=1

⇒90-18β2+36βα+2-18α+22=18

⇒5-β2+2αβ+4β-α2-4α-4=1

⇒α-β2+4α-β=0⇒α-β=0 or 4

As α and β are distinct |α-β|=4

Hence, the correct answer is 4.

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