Q43 / 90 · JEE Main 2024 (08 Apr Shift 1) · Mathematics

Let $f(x)=4 \cos ^3 x+3 \sqrt{3} \cos ^2 x-10$. The number of points of local maxima of $f$ in interval $(0,2 \pi)$ is

  • A
    3
  • B
    4
  • C
    1
  • Correct answer
    D
    2

Solution

$\begin{aligned} & \mathrm{f}(\mathrm{x})=4 \cos ^3(\mathrm{x})+3 \sqrt{3} \cos ^2(\mathrm{x})-10 ; \mathrm{x} \in(0,2 \pi) \\ & \Rightarrow \mathrm{f}^{\prime}(\mathrm{x})=12 \cos ^2 \mathrm{x}[-\sin (\mathrm{x})]+3 \sqrt{3}(2 \cos (\mathrm{x}))[-\sin (\mathrm{x})] \\ & \Rightarrow \mathrm{f}^{\prime}(\mathrm{x})=-6 \sin (\mathrm{x}) \cos (\mathrm{x})[2 \cos (\mathrm{x})+\sqrt{3}]\end{aligned}$ Figure
local maxima at $\mathrm{x}=\frac{5 \pi}{6}, \frac{7 \pi}{6}$

Hence, the correct answer is option: 'D'.

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