Q139 / 150 · MHT CET 2025 (23 Apr Shift 1) · Physics

Let the current 'I' be associated with an electron of charge 'e' moving in a circular orbit of radius ' $r$ ' with speed ' $v$ ' around the positively charged nucleus. The ratio $\frac{r}{v}$ is

  • A
    $\frac{\mathrm{e} \mathrm{I}}{2 \pi}$
  • B
    $\frac{2 \pi}{\mathrm{eI}}$
  • Correct answer
    C
    $\frac{\mathrm{e}}{2 \pi \mathrm{I}}$
  • D
    $\frac{2 \mathrm{e} \mathrm{I}}{\pi}$

Solution

The current $I$ for an electron of charge $e$ in a circular orbit equals the charge passing a point per unit time. Since charge $e$ passes a point each revolution period $T$, the current is given by $I = \frac{e}{T}$.

The time period for one orbit is $T = \frac{2\pi r}{v}$, where $r$ is the radius and $v$ is the orbital speed.

Combining these yields $I = \frac{e}{\frac{2\pi r}{v}} = \frac{ev}{2\pi r}$.

Rearranging to solve for the ratio $\frac{r}{v}$ gives $\frac{r}{v} = \frac{e}{2\pi I}$.

This expression corresponds to option C.

Hence, the correct answer is option: 'C'.

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