Q53 / 90 · JEE Main 2022 (27 Jun Shift 2) · Mathematics

Let t denote the greatest integer ≤t and t denote the fractional part of t. Then integral value of α for which the left hand limit of the function fx=1+x+α2x+x+x-12x+x at x=0 is equal to α-43 is _____

Correct answer: 3

Solution

Given,

fx=1+x+α2x+x+x-12x+x

limx→0-fx=α-43

limx→0-1+x+αx+x+x+x-12x+x=α-43

⇒0+α-1-2-1=α-43

⇒2-1α=α-43

⇒α+1α=103

On solving above equation we get,

⇒α=3;α∈I

Hence, the correct answer is 3.

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