Q36 / 75 · JEE Main 2020 (08 Jan Shift 2) · Mathematics

Let S, be the set of all functions f:0,1→R, which are continuous on 0,1, and differentiable on 0,1. Then for every f in S, there exists c∈0,1, depending on f, such that.

  • A
    fc-f1<1-cf'c
  • Correct answer
    B
    f1-fc1-c=f'c
  • C
    fc+f1<1+cf'c
  • D
    fc-f1<f'c

Solution

Let us consider fx, a constant function, as constant functions are continuous and differentiable everywhere.

Then, f1=fc & f'c=0

So, f1-fc1-c=f'c=0.

Hence, the correct answer is option: 'B'.

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