Q5 / 160 · TS EAMCET 2020 (10 Sep Shift 2) · Chemistry

Let's assume the $C_1 \equiv C_2$ bond is acetylene is along $Z$-axis. Find out the correct combination of atomic orbitals with non-zero overlapping.

  • A
    $2 p_x$ of $C_1$ and $2 p_y$ of $C_2$
  • B
    $2 p_z$ of $C_1$ and $2 p_y$ of $C_2$
  • C
    $2 p_x$ of $C_1$ and $2 s$ of $C_2$
  • Correct answer
    D
    $2 p_z$ of $C_1$ and $2 p_z$ of $C_2$

Solution

(d) In acetylene, we have $2 p_z$ of $\mathrm{C}_1$ and $2 p_z$ of $\mathrm{C}_2$ along $z$-axis, because both orbitals are $p$-orbitals and are in same direction, i.e. $z$-direction. The formula of acetylene is $\mathrm{CH} \equiv \mathrm{CH}$. Hence, option (d) is the correct answer.

Hence, the correct answer is option: 'D'.

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