Let p and q be roots of the equation x^2-2x+A=0 and let r and s be the roots of the equation x^2-18x+B=0. If p

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Let p and q be roots of the equation x^2-2x+A=0 and let r and s be the roots of the equation x^2-18x+B=0. If p<q<r<s are in arithmetic progression, then A and B are

MARKS Content Team · Accepted Answer

Correct answer: (C) -3,77. x^2-2x+A=0 ⇒ x=1±√(1-A) ∴ p=1-√(1-A),q=1+√(1-A) Similarly, r=9-√(81-B),s=9+√(81-B) p,q,r,s are in AP. ∵ q-p=s-r ⇒ 2√(1-A)=2√(81-B) ⇒ B=80+A and q-p=r-q ⇒ 3√(1-A)=8-√(81-B) ⇒ A=-3,B=77

Let $p$ and $q$ be roots of the equation $x^{2} - 2 x + A = 0$ and let $r$ and $s$ be the roots of the equation $x^{2} - 18 x + B = 0$ . If $p < q < r < s$ are in arithmetic progression, then $A$ and $B$ are

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Relevant Questions

Let p and q be roots of the equation x2-2x+A=0 and let r and s be the roots of the equation x2-18x+B=0. If p<q<r<s are in arithmetic progression, then A and B are

Solution

Relevant Questions

Let $p$ and $q$ be roots of the equation $x^{2} - 2 x + A = 0$ and let $r$ and $s$ be the roots of the equation $x^{2} - 18 x + B = 0$ . If $p < q < r < s$ are in arithmetic progression, then $A$ and $B$ are