Q29 / 92 · NTA Abhyas (JEE Main) 2020 · Mathematics · Parabola

Let lx-2y=1 intersects the parabola y2=4ax at points P and Q. If PS and QS meet the parabola again at R and T respectively (where S is the focus of y2=4ax ), then the slope of RT is equal to

Correct answer: 0.5

Solution

Let, P=t12,2t1 and Q=t22,2t2
Equation of PS is t1+t2y=2x+2t1t2
⇒ lines -2x+t1+t2y=2t1t2 and lx-2y=1 are same
⇒-2l=t1+t2-2=2t1t21
⇒t1+t2=4l & t1t2=-1l
Now, R=1t12,-2t1 and T=1t22,-2t2
The slope of RT is -2t2+2t11t22-1t12=-2t1-t2t1t2t1-t2t1+t2t12t22
=-2t1t2t1+t2=2l4l=12=0.5

Hence, the correct answer is 0.5.

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