Q62 / 120 · JEE Main 2007 · Mathematics
Let $A=\left[\begin{array}{ccc}5 & 5 \alpha & \alpha \\ 0 & \alpha & 5 \alpha \\ 0 & 0 & 5\end{array}\right]$. If $\left|A^2\right|=25$, then $|\alpha|$ equals
- A$5^2$
- B$1$
- Correct answerC$1 / 5$
- D$5$
Solution
$\mathrm{A}^2=\left[\begin{array}{ccc}5 & 5 \alpha & \alpha \\ 0 & \alpha & 5 \alpha \\ 0 & 0 & 5\end{array}\right]\left[\begin{array}{ccc}5 & 5 \alpha & \alpha \\ 0 & \alpha & 5 \alpha \\ 0 & 0 & 5\end{array}\right]$
$\mathrm{A}^2=\left[\begin{array}{ccc}25 & 25 \alpha+5 \alpha^2 & 5 \alpha+25 \alpha^2+5 \alpha \\ 0 & \alpha^2 & 5 \alpha^2+25 \alpha \\ 0 & 0 & 25\end{array}\right]$
$625 \alpha^2=25$
$\Rightarrow|\alpha|=\frac{1}{5}$.
Hence, the correct answer is option: 'C'.