Q62 / 120 · JEE Main 2007 · Mathematics

Let $A=\left[\begin{array}{ccc}5 & 5 \alpha & \alpha \\ 0 & \alpha & 5 \alpha \\ 0 & 0 & 5\end{array}\right]$. If $\left|A^2\right|=25$, then $|\alpha|$ equals

  • A
    $5^2$
  • B
    $1$
  • Correct answer
    C
    $1 / 5$
  • D
    $5$

Solution

$\mathrm{A}^2=\left[\begin{array}{ccc}5 & 5 \alpha & \alpha \\ 0 & \alpha & 5 \alpha \\ 0 & 0 & 5\end{array}\right]\left[\begin{array}{ccc}5 & 5 \alpha & \alpha \\ 0 & \alpha & 5 \alpha \\ 0 & 0 & 5\end{array}\right]$ $\mathrm{A}^2=\left[\begin{array}{ccc}25 & 25 \alpha+5 \alpha^2 & 5 \alpha+25 \alpha^2+5 \alpha \\ 0 & \alpha^2 & 5 \alpha^2+25 \alpha \\ 0 & 0 & 25\end{array}\right]$ $625 \alpha^2=25$ $\Rightarrow|\alpha|=\frac{1}{5}$.

Hence, the correct answer is option: 'C'.

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