Q31 / 60 · JEE Advanced 2015 (Paper 2) · Mathematics

Let fx=7tan8⁡x+7tan6⁡x-3tan4⁡x-3tan2⁡x  for all x∈ -π2,π2. Then the correct expression(S) is(are)

  • Correct answer
    A
    ∫0π4x fxdx=112
  • Correct answer
    B
    ∫0π4 fxdx=0
  • C
    ∫0π4x fxdx=16
  • D
    ∫0π4x fxdx=1

Solution

fx=7tan8⁡x+7tan6⁡x-3tan4⁡x-3tan2⁡x
fx=sec2⁡x7tan6⁡x-3tan2⁡x
Now,
∫0π4sec2⁡x7tan6⁡x-3tan2⁡x dx
=∫017t6-3t2dt
=7t77-3t33
=17-13=0
Also
∫0π4xsec2⁡x 7tan6⁡x-3tan2⁡x dx
tan⁡x=t
∫01tan-1⁡t7t6-3t2 dt
tan-1⁡tt7-t3|01-∫0111+t2 t7-t3dt
=-∫0111+t2 t3t4-1dt
=+∫01t3 1+t2 1-t2dt1+t2=∫01t3-t5dt
=14-16=112

Hence, the correct answer is options: 'A', 'B'.

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