Let fx= 3-x if x3 . Let α be the number of points of discontinuity of f and β be the number of points where f is not…

Question

Let fx= 3-x if x<-3 6 if -3≤x≤3 3+x if x>3 . Let α be the number of points of discontinuity of f and β be the number of points where f is not differentiable. Then α+β=

MARKS Content Team · Accepted Answer

Correct answer: (C) 2. The function is continuous everywhere, so number of points of discontinuity is α=0. The function is not differentiable at x=±3, so number of points of non-differentiability is β=2. Hence, α+β=2

Let $f (x) = \{\begin{matrix} 3 - x & if & x < - 3 \\ 6 & if & - 3 \leq x \leq 3 \\ 3 + x & if & x > 3 \end{matrix}$ . Let $α$ be the number of points of discontinuity of $f$ and $β$ be the number of points where $f$ is not differentiable. Then $α + β =$

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Let fx=3-xifx<-36if-3≤x≤33+xifx>3. Let α be the number of points of discontinuity of f and β be the number of points where f is not differentiable. Then α+β=

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Let $f (x) = \{\begin{matrix} 3 - x & if & x < - 3 \\ 6 & if & - 3 \leq x \leq 3 \\ 3 + x & if & x > 3 \end{matrix}$ . Let $α$ be the number of points of discontinuity of $f$ and $β$ be the number of points where $f$ is not differentiable. Then $α + β =$