Q35 / 200 · TS EAMCET 2001 · Chemistry
Let electronegativity, ionisation energy and electron affinity be represented as EN, IP and EA respectively. Which one of the following equation is correct according to Mulliken?
- A$\mathrm{EN}=\mathrm{IP} \times \mathrm{EA}$
- B$\mathrm{EN}=\frac{\mathrm{IP}}{\mathrm{EA}}$
- Correct answerC$\mathrm{EN}=\frac{\mathrm{IP}+\mathrm{EA}}{2}$
- D$\mathrm{EN}=\mathrm{IP}-\mathrm{EA}$
Solution
Mulliken suggested that EN of an element is the average of its IP and EA.
Hence, the correct answer is option: 'C'.