Q65 / 100 · BITSAT 2024 (Memory Based Paper 1) · Mathematics

Let $p, q, r$ be three logical statements. Consider the compound statements $S_1:((\sim p) \vee q) \vee((\sim p) \vee r)$ and $S_2: p \rightarrow(q \vee r)$ Then, which of the following is NOT true?

  • A
    If $S_2$ is true, then $S_1$ is true
  • B
    If $S_2$ is false, then $S_1$ is false
  • Correct answer
    C
    If $S_2$ is false, then $S_1$ is true
  • D
    If $S_1$ is false, then $S_2$ is false

Solution

Given statement $S_1:(\sim p \vee q) \vee(\sim p \vee r)$ $\equiv \sim p \vee(q \vee r)$ $S_2: p \rightarrow(q \vee r)$ $\equiv \sim p \vee(q \vee r) \rightarrow$ By conditional law $S_1 \equiv S_2$

Hence, the correct answer is option: 'C'.

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