Q65 / 100 · BITSAT 2024 (Memory Based Paper 1) · Mathematics
Let $p, q, r$ be three logical statements. Consider the compound statements
$S_1:((\sim p) \vee q) \vee((\sim p) \vee r)$ and
$S_2: p \rightarrow(q \vee r)$
Then, which of the following is NOT true?
- AIf $S_2$ is true, then $S_1$ is true
- BIf $S_2$ is false, then $S_1$ is false
- Correct answerCIf $S_2$ is false, then $S_1$ is true
- DIf $S_1$ is false, then $S_2$ is false
Solution
Given statement $S_1:(\sim p \vee q) \vee(\sim p \vee r)$
$\equiv \sim p \vee(q \vee r)$
$S_2: p \rightarrow(q \vee r)$
$\equiv \sim p \vee(q \vee r) \rightarrow$ By conditional law
$S_1 \equiv S_2$
Hence, the correct answer is option: 'C'.