Q48 / 68 · NEST (NISER) 2023 (Session 2) · Mathematics

Let $N$ be the number of solutions of the equation
$x_0+2 x_1+2 x_2+2 x_3+2 x_4+x_5=6$
with $x_0, x_1, x_2, x_3, x_4$ and $x_5$ taking non-negative integer values. Then

  • A
    $N \lt 50$
  • Correct answer
    B
    $50 \leq N \lt 100$
  • C
    $100 \leq N \lt 1000$
  • D
    $1000 \leq N$

Hence, the correct answer is option: 'B'.

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