Q48 / 68 · NEST (NISER) 2023 (Session 2) · Mathematics
Let $N$ be the number of solutions of the equation
$x_0+2 x_1+2 x_2+2 x_3+2 x_4+x_5=6$
with $x_0, x_1, x_2, x_3, x_4$ and $x_5$ taking non-negative integer values. Then
$x_0+2 x_1+2 x_2+2 x_3+2 x_4+x_5=6$
with $x_0, x_1, x_2, x_3, x_4$ and $x_5$ taking non-negative integer values. Then
- A$N \lt 50$
- Correct answerB$50 \leq N \lt 100$
- C$100 \leq N \lt 1000$
- D$1000 \leq N$
Hence, the correct answer is option: 'B'.