Let $a_1, a_2, \ldots, a_{2022}$ be positive integers such that $a_i+a_{i+1}=b+1$ for $1 \leq i \leq 2021$, where $b$ is a constant. If $a_{202}=2$, then $a_{22}$ is

• A

  $1$
• Correct answer
  B

  $2$
• C

  $b-1$
• D

  $b$

Hence, the correct answer is option: 'B'.