Q103 / 225 · JEE Main 2005 · Mathematics
Let $f$ be differentiable for all $x$. If $f(1)=-2$ and $f^{\prime}(x) \geq 2$ for $x \in[1,6]$, then
- Correct answerA$f(6) \geq 8$
- B$f(6) < 8$
- C$f(6) < 5$
- D$f(6)=5$
Solution
As $f(1)=-2 \quad \& f^{\prime}(x) \geq 2 \quad \forall x \in[1,6]$
Applying Lagrange's mean value theorem
$$
\begin{aligned}
& \frac{f(6)-f(1)}{5}=f^{\prime}(c) \geq 2 \\
& \Rightarrow f(6) \geq 10+f(1) \\
& \Rightarrow f(6) \geq 10-2 \\
& \Rightarrow f(6) \geq 8 .
\end{aligned}
$$
Hence, the correct answer is option: 'A'.