Q43 / 90 · JEE Main 2012 (26 May Online) · Mathematics
Let $f:(-\infty, \infty) \rightarrow(-\infty, \infty)$ be defined by $f(x)=x^3+1$
Statement 1: The function fhas a local extremum at $x=0$
Statement 2: The function $f$ is continuous and differentiable on $(-\infty, \infty)$ and $f^{\prime}(0)=0$
- AStatement 1 is true, Statement 2 is false.
- BStatement 1 is true, Statement 2 is true, Statement 2 is a correct explanation for Statement 1.
- CStatement 1 is true, Statement 2 is true, Statement 2 is not the correct explanation for Statement 1.
- Correct answerDStatement 1 is false, Statement 2 is true.
Solution
Let $f:(-\infty, \infty) \rightarrow(-\infty, \infty)$ be defined by $f(x)=x^3+1$.
Clearly, $f(x)$ is symmetric along $y=1$ and it has neither maxima nor minima.
$\therefore$ Statement - 1 is false.
Hence, the correct answer is option: 'D'.