Let $\triangle A B C$ be an equilateral triangle with each side being of length equal to 2 . We construct three discs with centres at the points $A, B$ and $C$ respectively, each having radius equal to $\sqrt{2}$.



Then the area of the region common to all three discs is

• A

  $2 \sqrt{3}-\pi$
• Correct answer
  B

  $\sqrt{3}+\pi / 2-3$
• C

  $\sqrt{3}+16 / 9-\pi$
• D

  $9 / 4+\sqrt{3}-\pi$

Hence, the correct answer is option: 'B'.