Q20 / 54 · JEE Advanced 2022 (Paper 1) · Mathematics

Let α be a positive real number. Let f:ℝ→ℝ and g:α,∞→ℝ be the functions defined by fx=sinπx12 and gx=2logex-αlogeex-eα.
Then the value of limx→α+fgx is ______.

Correct answer: 0.5

Solution

limx→α+gx=limx→α+2logex-αlogeex-eα=limx→α+2x-α12x1ex-eα12xex

=limx→α+ex-eαx-α1ex·2

=2eαlimx→α+ex·12x12x=2

limx→α+fgx=flimx→α+gx

=f2=sinπ6=12=0.50

Hence, the correct answer is 0.5.

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