Q27 / 75 · JEE Main 2025 (3 Apr Shift 2) · Mathematics
Let $\mathrm{f}: \mathrm{R} \rightarrow \mathrm{R}$ be a function defined by $f(x)=\|x+2|-2| x\|$. If $m$ is the number of points of local minima and $n$ is the number of points of local maxima of $f$, then $m+n$ is
- A$5$
- Correct answerB$3$
- C$2$
- D$4$
Solution
$f(x)=\|x+2|-2| x\|$
Critical points, $0,-2,2,-\frac{2}{3}$

No. of maxima $=1$
No. of minima $=2$
option (2)
Critical points, $0,-2,2,-\frac{2}{3}$

No. of maxima $=1$
No. of minima $=2$
option (2)
Hence, the correct answer is option: 'B'.