Let $f: N \rightarrow Y$ be a function defined as $f(x)=4 x+3$, where $Y=\{y \in N: y=4 x+3$ for some $x \in N\}$. Show that $\mathrm{f}$ is invertible and its inverse is

• A

  $g(y)=\frac{3 y+4}{3}$
• B

  $g(y)=4+\frac{y+3}{4}$
• C

  $g(y)=\frac{y+3}{4}$
• Correct answer
  D

  $g(y)=\frac{y-3}{4}$

Hence, the correct answer is option: 'D'.