Q49 / 155 · WBJEE 2020 · Mathematics

Let $f$ be a differentiable function with $\lim _{x \rightarrow \infty} f(x)=0 .$ If $y^{\prime}+y f^{\prime}(x)-f(x) f^{\prime}(x)=0, \lim _{x \rightarrow \infty} y(x)=0$, then $\left(\right.$ where $\left.y^{\prime}=\frac{d y}{d x}\right)$

  • A
    $y+1=e^{f(x)}+f(x)$
  • B
    $y-1=e^{f(x)}+f(x)$
  • Correct answer
    C
    $y+1=e^{-f(x)}+f(x)$
  • D
    $y-1=e^{-f f] x}+f(x)$

Solution

Hint: $\frac{d y}{d x}+f^{\prime}(x) y=f^{\prime}(x) f(x)$ $\Rightarrow y \times e^{f(x)}=\int f^{\prime}(x) f(x) e^{f(x)} d x$ $\Rightarrow y \times e^{f(x)}=e^{f(x)}(f(x)-1)+c \quad[$ Putting $f(x)=0 ; y=0, c=1]$ $\Rightarrow y \times e^{f(x)}=e^{f(x)}(f(x)-1)+1$ $\Rightarrow y=f(x)-1+e^{-f(x)}$ $\Rightarrow y+1=e^{-f(x)}+f(x)$

Hence, the correct answer is option: 'C'.

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