Q42 / 160 · AP EAMCET 2025 (27 MAY SHIFT 1) · Mathematics

Let $g(x)=1+x-[x]$ and $f(x)= \begin{cases}-1, & x < 0 \\ 0, & x=0 \\ 1, & x>0\end{cases}$ \([x]\) denotes the greatest integer less than or equal to \(x\). Then for all $\mathrm{x}, \mathrm{f}(\mathrm{g}(\mathrm{x}))=$

  • Correct answer
    A
    $1$
  • B
    x
  • C
    $f(x)$
  • D
    $g(x)$

Hence, the correct answer is option: 'A'.

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