Q192 / 270 · NDA 2023 (Phase 2) · Mathematics

Let $f(x)=x^2-1$ and $\operatorname{gof}(x)=x-\sqrt{x}+1$ What is g(15) equal to?

  • A
    1
  • B
    2
  • Correct answer
    C
    3
  • D
    4

Solution

Since, $g(x)=\sqrt{1+x}-\sqrt[4]{1+x}+1$ $\Rightarrow g(15)=\sqrt{16}-\sqrt[4]{16}+1=4-2+1=3$

Hence, the correct answer is option: 'C'.

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