Let $\left(1+x+x^{2}\right)^{2014}=a_{0}+a_{1} x+a_{2} x^{2}+a_{3} x^{3}+\ldots . .+a_{s+28} x^{4028}$ and let $$ \begin{array}{l} A=a_{0}-a_{3}+a_{6}-\ldots \ldots+a_{4026} \\ B=a_{1}-a_{4}+a_{7}-\ldots \ldots .-a_{4027} \\ C=a_{2}-a_{5}+a_{8}-\ldots \ldots .+a_{4028} \end{array} $$ Then

• A

  $|A|=|B|>|C|$
• B

  $|A|=|B| < |C|$
• Correct answer
  C

  $|A|=|C|>|B|$
• D

  $|A|=|C| < |B|$

Hence, the correct answer is option: 'C'.