Let $\omega_1, \omega_2$ and $\omega_3$ be the angular speed of the second hand, minute hand and hour hand of a smoothly running analog clock, respectively. If $x_1, x_2$ and $x_3$ are their respective angular distances in 1 minute then the factor which remains constant $(k)$ is

• Correct answer
  A

  $\frac{\omega_1}{x_1}=\frac{\omega_2}{x_2}=\frac{\omega_3}{x_3}=k$
• B

  $\omega_1 x_1=\omega_2 x_2=\omega_3 x_3=k$
• C

  $\omega_1 x_1^2=\omega_2 x_2^2=\omega_3 x_3^2=k$
• D

  $\omega_1^2 x_1=\omega_2^2 x_2=\omega_3^2 x_3=k$

Hence, the correct answer is option: 'A'.