Q46 / 75 · JEE Main 2025 (7 Apr Shift 1) · Mathematics

Let ABC be the triangle such that the equations of lines $A B$ and $A C$ be $3 y-x=2$ and $x+y=2$, respectively, and the points B and C lie on x -axis. If $P$ is the orthocentre of the triangle $A B C$, then the area of the triangle PBC is equal to

  • A
    4
  • B
    10
  • C
    8
  • Correct answer
    D
    6

Solution

Figure
$\begin{aligned} & \text { Equation of Altitude } \mathrm{AP}: \mathrm{x}=1 \\ & \text { Equation of Altitude } \mathrm{BP}: \mathrm{y}-0=1(\mathrm{x}+2) \\ & \Rightarrow \mathrm{x}=1 \& \\ & \mathrm{x}-\mathrm{y}+2=0 \\ & \mathrm{P}(1,3) \\ & \text { Area of } \triangle \mathrm{PBC}=\frac{1}{2} \times 4 \times 3=6\end{aligned}$

Hence, the correct answer is option: 'D'.

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