Let a → = i ^ +2 j ^ +3 k ^ , b → =2 i ^ +3 j ^ + k ^ , c → = k ^ + i ^ and x→×b→=a→×c→×b→. If x→⋅a→=0, then x→ is equal to use √3=1.73)

Question

MARKS Content Team · Accepted Answer

Correct answer: 3.46. x→×b→=a→⋅b→c→-b→⋅c→a→=11c→-3a→ As, a→⋅b→=11 and b→⋅c→=3 Now x→×b→×a→=11c→×a→ ⇒x→⋅a→b→-b→⋅a→x→=11c→×a→ ⇒x→=a→×c→ as a→⋅x→=0 ⇒x→= i^ j^ k^ 1 2 3 1 0 1 =2i^+2j^-2k^ ⇒x→=2√3 =3.46

Let $\vec{a} = \hat{i} + 2 \hat{j} + 3 \hat{k},$ $\vec{b} = 2 \hat{i} + 3 \hat{j} + \hat{k},$ $\vec{c} = \hat{k} + \hat{i}$ and $(\vec{x} \times \vec{b}) = (\vec{a} \times \vec{c}) \times \vec{b}$ . If $\vec{x} \cdot \vec{a} = 0$ , then $|\vec{x}|$ is equal to
use $\sqrt{3} = 1.73$ )

Solution

More Vector Algebra Questions

Let a → = i ^ +2 j ^ +3 k ^ , b → =2 i ^ +3 j ^ + k ^ , c → = k ^ + i ^ and x→×b→=a→×c→×b→. If x→⋅a→=0, then x→ is equal to use 3=1.73)

Solution

More Vector Algebra Questions

Let $\vec{a} = \hat{i} + 2 \hat{j} + 3 \hat{k},$ $\vec{b} = 2 \hat{i} + 3 \hat{j} + \hat{k},$ $\vec{c} = \hat{k} + \hat{i}$ and $(\vec{x} \times \vec{b}) = (\vec{a} \times \vec{c}) \times \vec{b}$ . If $\vec{x} \cdot \vec{a} = 0$ , then $|\vec{x}|$ is equal to
use $\sqrt{3} = 1.73$ )