Q252 / 270 · NDA 2017 (Phase 2) · Mathematics

Let a die be loaded in such a way that even faces are twice likely to occur as the odd faces. What is the probability that a prime number will show up when the die is tossed?

  • A
    $\frac{1}{3}$
  • B
    $\frac{2}{3}$
  • Correct answer
    C
    $\frac{4}{9}$
  • D
    $\frac{5}{9}$

Solution

Possible prime numbers on the dice are 2,3 and 5 . $\text { Probability of getting prime number }=\frac{2}{3} \times \frac{1}{3}+\frac{1}{3} \times \frac{2}{3} \text {. }$ $\begin{aligned} & =\frac{2}{9}+\frac{2}{9} \\ & =\frac{4}{9} .\end{aligned}$

Hence, the correct answer is option: 'C'.

Relevant Questions