Let A be a point having position vector $\bar{i}-3 \bar{j}$ and $\bar{r}=(\bar{i}-3 \bar{j})+t(\bar{j}-2 \bar{k})$ be a line. If P is a point on this line and is at a minimum distance from the plane $\bar{r} \bullet(2 \bar{i}+3 \bar{j}+5 \bar{k})=0$, then the equation of the plane through P and perpendicular to AP, is

• Correct answer
  A

  $\bar{r} \cdot(-\bar{j}+2 \bar{k})=8$
• B

  $\bar{r} \cdot(\bar{j}+\bar{k})=4$
• C

  $\bar{r} \cdot(\bar{i}+\bar{j}+\bar{k})=8$
• D

  $\bar{r} \cdot(\bar{i}-\bar{j})=12$

Hence, the correct answer is option: 'A'.