Q44 / 75 · JEE Main 2020 (09 Jan Shift 2) · Mathematics

Let a→,b→ and c→ be three vectors such that a→=3,b→=5,b→∙c→=10 and the angle between b→ and c→ is π3. If a→ is perpendicular to the vector b→×c→, then a→×b→×c→ is equal to ____________.

Correct answer: 30

Solution

b→.c→=10⇒b→c→cos⁡π3=10⇒5.c→.12=10

⇒c→=4

Also, a→.b→×c→=0

a→×b→×c→=a→b→×c→sin⁡π2

⇒3×b→c→sin⁡π3×1

⇒3×5×4×32=30

Hence, the correct answer is 30.

Relevant Questions