Q42 / 91 · KVPY 2020 (SB/SX) · Mathematics

Let A=aij1≤i,j¯3 be a 3×3 invertible matrix where each aii is a real number. Denote the inverse of the matrix A by A-1. If ∑itl3aij=1
for 1≤i≤3, then

  • A
    sum of the diagonal entries of A is 1
  • Correct answer
    B
    sum of each row of A-1 is 1
  • C
    sum of each row and each column of A-1 is 1
  • D
    sum of the diagonal entries of A-1 is 1

Solution

Sum of elements in each row of A is 1.

So, A111=111
⇒A-1 A111=A-1111
⇒111=A-1111
⇒ sum of elements in each row of A-1 is 1

Hence, the correct answer is option: 'B'.

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