Q18 / 100 · NTA Abhyas (JEE Main) 2020 · Mathematics · Vector Algebra

Let 2a→=b→×c→+2b→ where a→, b→ and c→ are three unit vectors, then sum of all possible values of 3a→+4b→+5c→ is

  • A
    10
  • B
    12
  • Correct answer
    C
    14
  • D
    16

Solution

2a→=b→×c→+2b→
Taking dot with b→
2a→⋅b→=2b→2⇒a→⋅b→=1
⇒a→=b→ also b→×c→=0 (from given equation)
⇒b→=c→ or b→=-c→
So, if b→=c→, then 3a→+3b→+5c→=12
or if b→=-c→, then 3a→+4b→+5c→=2

Hence, the correct answer is option: 'C'.

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