Q43 / 180 · AIIMS 2007 · Chemistry

Largest difference in radii is found in case of the pair

  • A
    \(\mathrm{Li}, \mathrm{Na}\)
  • Correct answer
    B
    \(\mathrm{Na}, \mathrm{K}\)
  • C
    \(\mathrm{K}, \mathrm{Rb}\)
  • D
    \(\mathrm{Rb}, \mathrm{Cs}\).

Solution

Atomic as well as ionic radii increases from \(\mathrm{Li}\) to Fr due to the presence of one extra shell of electron. \(\begin{array}{llllll} & \mathrm{Li} & \mathrm{Na} & \mathrm{K} & \mathrm{Rb} & \mathrm{Cs} \\ \text { Metallic radii (pm) } & 152 & 186 & 227 & 248 & 265\end{array}\)

Hence, the correct answer is option: 'B'.

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