Q17 / 200 · Manipal (MET) 2013 · Chemistry
${ }_7^{14} \mathrm{~N}+{ }_0^1 n \rightarrow{ }_6^{14} \mathrm{C}+{ }_1^1 \mathrm{H}$ is written as
- A${ }_7^{14} \mathrm{~N}(n, e){ }_1^1 \mathrm{H}$
- B${ }_7^{14} \mathrm{~N}(p, n){ }_6^{14} \mathrm{C}$
- Correct answerC${ }_7^{14} \mathrm{~N}(n, p){ }_6^{14} \mathrm{C}$
- D${ }_6^{14} \mathrm{C}(p, n){ }_7^{14} \mathrm{~N}$
Solution
${ }_7^{14} \mathrm{~N}+{ }_0^1 n \longrightarrow{ }_6^{14} \mathrm{C}+{ }_1^1 \mathrm{H}$
This reaction can be represented as
${ }_7^{14} \mathrm{~N}(n, p){ }_6^{14} \mathrm{C}$
Hence, the correct answer is option: 'C'.