Q83 / 180 · KCET 2007 · Mathematics

$A B C$ is triangle, $G$ is the centroid, $D$ is the mid-point of $B C$. If $A=(2,3)$ and $G=(7,5)$, then the point $D$ is

  • A
    $\left(\frac{9}{2}, 4\right)$
  • Correct answer
    B
    $\left(\frac{19}{2}, 6\right)$
  • C
    $\left(\frac{11}{2}, \frac{11}{2}\right)$
  • D
    $\left(8, \frac{13}{2}\right)$

Solution

Since, $D$ is the mid-point of $B C$. So, coordinate of $B C$ are $\left(\frac{x_{2}+x_{3}}{2}, \frac{y_{2}+y_{3}}{2}\right)$ Given, $G(7,5)$ is the centroid of $\triangle A B C$. $\therefore \quad 7=\frac{2+x_{2}+x_{3}}{3}$ and $5=\frac{3+y_{2}+y_{3}}{3}$ $\Rightarrow \quad x_{2}+x_{3}=21-2$ and $\quad y_{2}+y_{3}=15-3$ $\begin{array}{ll}\Rightarrow & x_{2}+x_{3}=19 \\ \text { and } & y_{2}+y_{3}=12\end{array}$
Figure
$\Rightarrow \quad \frac{x_{2}+x_{3}}{2}=\frac{19}{2}$ and $\quad \frac{y_{2}+y_{3}}{2}=6$ $\therefore$ Coordinate of $D$ are $\left(\frac{19}{2}, 6\right)$.

Hence, the correct answer is option: 'B'.

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