Q21 / 75 · JEE Main 2025 (4 Apr Shift 1) · Chemistry

$X Y$ is the membrane / partition between two chambers 1 and 2 containing sugar solutions of concentration $c_1$ and $c_2\left(c_1 \gt c_2\right) \mathrm{mol} \mathrm{L}^{-1}$. For the reverse osmosis to take place identify the correct condition
(Here $p_1$ and $p_2$ are pressures applied on chamber 1 and 2)
Figure
(A) Membrane/Partition; Cellophane, $\mathrm{p}_1 \gt \pi$
(B) Membrane/Partition ; Porous. $\mathrm{p}_2 \gt \pi$
(C) Membrane/Partition ; Parchment paper, $\mathrm{p}_1 \gt \pi$
(D) Membrane/Partition : Cellophane, $\mathrm{p}_2 \gt \pi$
Choose the correct answer from the option given below :

  • A
    B and D only
  • B
    A and D only
  • Correct answer
    C
    A and C only
  • D
    C only

Solution

Figure
Normal osmosis occurs from (2) to (1)
For reverse osmosis from (1) to (2)
Pressure : $\mathrm{P}_1 \gt \pi$
$\therefore$ Answer [A \& C] only

Hence, the correct answer is option: 'C'.

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