Q140 / 200 · Manipal (MET) 2013 · Mathematics
$(\sim p \wedge q)$ is logically equivalent to
- A$p \rightarrow q$
- B$q \rightarrow p$
- C$\sim(p \rightarrow q)$
- Correct answerD$\sim(q \rightarrow p)$
Solution
$\sim p \wedge q=\sim(q \rightarrow p)$
Hence, the correct answer is option: 'D'.