Q115 / 160 · AP EAMCET 2008 · Mathematics

$\int_{-\pi / 2}^{\pi / 2} \sin |x| d x$ is equal to

  • A
    $0$
  • B
    $1$
  • Correct answer
    C
    $2$
  • D
    $\pi$

Solution

Let $$ \begin{aligned} I & =\int_{-\pi / 2}^{\pi / 2} \sin |x| d x \\ & =2 \int_0^{\pi / 2} \sin x d x \\ & =2[-\cos x]_0^{\pi / 2} \\ & =2 \end{aligned} $$

Hence, the correct answer is option: 'C'.

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