Q61 / 180 · COMEDK 2020 · Mathematics
$7^{2 \log _{7} 5}$ is equal to
- A5
- B$\log _{7} 35$
- C$\log _{7} 25$
- Correct answerD25
Solution
We have,
$7^{2 \log 5} 5$
$=7^{\log _{7} 5^{2}}$
$=5^{2}$
[ $m \log a=\log a^{m}$ ]
$\left[a^{\log _{a} b}=b\right]$
$=25$
Hence, the correct answer is option: 'D'.