Q102 / 180 · KCET 2025 · Mathematics

$\lim _{x \rightarrow 1} \frac{x^4-\sqrt{x}}{\sqrt{x}-1}$ is

  • A
    $0$
  • Correct answer
    B
    $7$
  • C
    Does not exist
  • D
    $\frac{1}{2}$

Solution

$\begin{gathered}\lim _{x \rightarrow 1} \frac{x^4-\sqrt{x}}{\sqrt{x}-1}=\lim _{x \rightarrow 1} \frac{4 x^3-\frac{1}{2 \sqrt{x}}}{\frac{1}{2 \sqrt{x}}}=\lim _{x \rightarrow 1} \frac{\frac{8 x^3 \sqrt{x}-1}{2 \sqrt{4}}}{\frac{1}{2 \sqrt{x}}} \\ =7\end{gathered}$

Hence, the correct answer is option: 'B'.

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