Q102 / 180 · KCET 2025 · Mathematics
$\lim _{x \rightarrow 1} \frac{x^4-\sqrt{x}}{\sqrt{x}-1}$ is
- A$0$
- Correct answerB$7$
- CDoes not exist
- D$\frac{1}{2}$
Solution
$\begin{gathered}\lim _{x \rightarrow 1} \frac{x^4-\sqrt{x}}{\sqrt{x}-1}=\lim _{x \rightarrow 1} \frac{4 x^3-\frac{1}{2 \sqrt{x}}}{\frac{1}{2 \sqrt{x}}}=\lim _{x \rightarrow 1} \frac{\frac{8 x^3 \sqrt{x}-1}{2 \sqrt{4}}}{\frac{1}{2 \sqrt{x}}} \\ =7\end{gathered}$
Hence, the correct answer is option: 'B'.