Q112 / 180 · KCET 2010 · Mathematics
$\int_{0}^{1} x(1-x)^{3 / 2} d x$ is
- A$-\frac{2}{35}$
- Correct answerB$\frac{4}{35}$
- C$\frac{24}{35}$
- D$-\frac{8}{35}$
Solution
$\int_{0}^{1} x(1-x)^{3 / 2} d x$
$=\int_{0}^{1} \mathrm{x}^{(2-1)}(1-\mathrm{x})^{5 / 2-1} \mathrm{dx}$
$=\mathrm{B}(2,5 / 2)\left\{\begin{array}{l}\because \mathrm{B}(\mathrm{m}, \mathrm{n})=\int_{0}^{1} \mathrm{x}^{\mathrm{m}-1}(1-\mathrm{x})^{\mathrm{n}-1} \mathrm{dx} \\ \because \mathrm{B}(\mathrm{m}, \mathrm{n})=\frac{\Gamma \mathrm{m} \Gamma \mathrm{n}}{\Gamma(\mathrm{m}+\mathrm{n})}\end{array}\right.$
$=\frac{\Gamma 2 \Gamma 5 / 2}{\Gamma(2+5 / 2)}$
$=\frac{1 \cdot 3 / 2 \cdot 1 / 2 \Gamma 1 / 2}{\Gamma 9 / 2} \quad(\because \Gamma 1 / 2=\sqrt{\pi})$
$=\frac{3 / 4 \cdot \sqrt{\pi}}{7 / 2 \cdot 5 / 2 \cdot 3 / 2 \cdot 1 / 2 \sqrt{\pi}}=\frac{4}{35}$
Hence, the correct answer is option: 'B'.