Q17 / 90 · KVPY 2014 (SB/SX) · Chemistry

$\mathrm{Ni}(\mathrm{CO})_{4}$ is :

A
tetrahedral and paramagnetic
B
square planar and diamagnetic
Correct answer
C
tetrahedral and diamagnetic
D
square planar and paramagnetic

Solution

$\quad \mathrm{Ni}(\mathrm{CO})_{4}$ is tetrahedral with $\mathrm{d}^{10}$ configuration

Hence, the correct answer is option: 'C'.

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